grep question (Solved)
Posted: Mon Oct 12, 2020 11:06 pm
Hi.
I want to get the entry of Name= and Exec= from a .desktop file.
Usually I'm doing it using the commands below:
This works good as long as there's not multiple Name= and Exec= entries in the .desktop file.
Now I have a problem with some .desktop files, as there's multiple Name= and Exec= entries included.
I only want to get the first of them under [Desktop Entry] and all others suppressed/excluded.
How could I achieve this using shell script commands?
Thanks.
I want to get the entry of Name= and Exec= from a .desktop file.
Usually I'm doing it using the commands below:
Code: Select all
MENUPROGNAME=$(grep "^Name=" $MENUTMPLT|sed 's/\Name=//')Code: Select all
MENUPROGNAME=$(grep "^Exec=" $MENUTMPLT|sed 's/\Exec=//')Now I have a problem with some .desktop files, as there's multiple Name= and Exec= entries included.
Code: Select all
[Desktop Entry]
Version=1.0
Type=Application
Name=Stellarium
Name[af]=Stellarium
... snippet...
#Exec=stellarium --startup-script=%f
Exec=stellarium
Icon=stellarium
StartupNotify=false
Terminal=false
Categories=Astronomy;Education;Science;
Comment=Planetarium
Comment[af]=Planetarium
Comment[ar]=قبة سماوية
[Desktop Action Window]
Name=Open in window
Name[af]=Maak in 'n nuwe skerm oop
... snippet...
Exec=stellarium -f no
[Desktop Action Fullscreen]
Name=Open in fullscreen
Name[af]=Maak in 'n volskerm oop
... snippet...
Exec=stellarium -f yes
[Desktop Action Debugmode]
Name=Open in debug mode
Name[af]=Open in ontfout wyse
... snippet...
Exec=stellarium --dump-opengl-detailsHow could I achieve this using shell script commands?
Thanks.
