SED question (Solved in a different way)

[taersh]

Hi.

From a path and file name

Code: Select all

\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav

I need to remove this leading part

Code: Select all

\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\

How to do this?

[fredx181]

Hi Rainer, I think by escaping all the backward slashes, so gets double: \\

Code: Select all

echo "\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav" | sed -e 's|\\mnt\\sdb1\\LoopsAndSamples\\Movie_Score_Vol5\\||'

Works but maybe there's a more simple way.
EDIT: BTW are you sure the string/path has backward slashes? That's the Windows way.

Fred

[taersh]

Thanks!

But how would I do it if the path is stored into a variable?
E.g.: BSPATH="\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav"

Yes, it has backslashes. It's content from a .sfz file.

[Trapster]

Maybe this?

Code: Select all

echo '\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav' | sed 's/\\/\//g' | xargs -n 1 basename

changes the backslashes to forward and then pulls the filename.

[fredx181]

But how would I do it if the path is stored into a variable?
E.g.: BSPATH="\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav"

I would understand the question if the leading part you want to remove is a variable

Maybe you can clarify some more about what exactly you do, If I understand correctly, you want the output:
Harp\Harp_a_1.wav

Fred

[taersh]

Yes, I want to have only this part: Harp\Harp_a_1.wav or \Harp\Harp_a_1.wav remaining from the full path and name.

I want to change the full paths inside of a .sfz file.

So, the .sfz file should not search for the .wav file by full path, but related to its location.
The full path to the .wav file would be \mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav.
But I want to change that full path to relative path. So, Harp\Harp_a_1.wav or even \Harp\Harp_a_1.wav.

Example:

This: <region> lovel=1 hivel=127 sample=\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav
should change to
this: <region> lovel=1 hivel=127 sample=Harp\Harp_a_1.wav
or even to
this: <region> lovel=1 hivel=127 sample=\Harp\Harp_a_1.wav

[taersh]

Thanks for the suggestions.

I could solve this another way.
Instead of submitting the full path of the samples to the program that creates the .sfz file, I'm jumping (cd ParentDir) into the parent directory and then submitting only the relative path of the samples to the program. So, by now the created <region> lines are all looking like this one:

Code: Select all

<region> lovel=1 hivel=127 sample=Harp\Harp_a_1.wav

Testing in Konfyt Keyboard Workstation resulted successful. The samples could be played by the UBS MIDI keyboard.

So, problem solved without to solve the SED question.

[MochiMoppel]

This: <region> lovel=1 hivel=127 sample=\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav
should change to
this: <region> lovel=1 hivel=127 sample=Harp\Harp_a_1.wav

FULL='<region> lovel=1 hivel=127 sample=\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav'
REMOVE='\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\'
echo ${FULL/"$REMOVE"}

[taersh]

@MochiMoppel
Since I'm not getting any final success in my development I'm going to use your suggestion.
It's closer to my basic idea and might help on where I'm currently hacking now for hours without having any remarkable progress.

Thanks!

[stemsee]

ugly solution using g/awk

Code: Select all

echo "\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav" | gawk -F'\' '{$1=""; $2=""; $3=""; $4=""; print $0}' | cut -c4-$$ | tr ' ' '\\'

[stemsee]

Thanks!

But how would I do it if the path is stored into a variable?
E.g.: BSPATH="\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav"

Yes, it has backslashes. It's content from a .sfz file.

Code: Select all

BSPATH="\mnt\sdb1\LoopsAndSamples\Movie_Score_Vol5\Harp\Harp_a_1.wav"
echo "$BSPATH"  | rev | cut -d'\' -f1,2 | rev